f(x) = 6x² - 9x + 5
--› tentukan
f'(x) = ...
f'(3) = ...![]()
--› tentukan
f'(x) = ...
f'(3) = ...
Jawaban:
[tex] \boxed{\sf f'(x) = 12 x - 9}[/tex]
[tex] \boxed{\sf f'(3) = 27}[/tex]
...
[tex] \sf f(x) = {6x}^{2} - 9x + 5[/tex]
[tex] \sf f'(x) = {6.2 \: x}^{2 - 1} - 9.1 \: {x}^{1 - 1} + 0[/tex]
[tex] \sf f'(x) = {12 x}^{ 1} - 9 {x}^{0} [/tex]
[tex] \sf f'(x) = 12 x - 9 .1[/tex]
[tex] \boxed{\sf f'(x) = 12 x - 9}[/tex]
...
[tex] \sf f'(x) = {12 x}^{} - 9 x[/tex]
[tex] \sf f'(3) = 12(3) - 9[/tex]
[tex] \sf f'(3) = 36 - 9[/tex]
[tex] \boxed{\sf f'(3) = 27}[/tex]
f(x) = 6x² - 9x + 5
--› tentukan
f'(x) = ...
f'(3) = ...
_____________
No 1
f'(x) = 2 × 6 × x²‾¹ - 1 × 9 × x¹‾¹ + 0
f'(x) = 12x¹ - 9x⁰
f'(x) = 12x - 9
No 2
f'(3) = 12(3) - 9
f'(3) = 36 - 9
f'(3) = 27
[answer.2.content]
